-0.03x^2+21=0

Solution for -0.03x^2+21=0 equation:

-0.03x^2+21=0

a = -0.03; b = 0; c = +21;
Δ = b2-4ac
Δ = 02-4·(-0.03)·21
Δ = 2.52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{2.52}}{2*-0.03}=\frac{0-\sqrt{2.52}}{-0.06}
=-\frac{\sqrt{}}{-0.06}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{2.52}}{2*-0.03}=\frac{0+\sqrt{2.52}}{-0.06}
=\frac{\sqrt{}}{-0.06}
$